0=21x^2+56x

Solution for 0=21x^2+56x equation:

0=21x^2+56x

We move all terms to the left:

0-(21x^2+56x)=0

We add all the numbers together, and all the variables

-(21x^2+56x)=0

We get rid of parentheses

-21x^2-56x=0

a = -21; b = -56; c = 0;
Δ = b2-4ac
Δ = -562-4·(-21)·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-56}{2*-21}=\frac{0}{-42}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+56}{2*-21}=\frac{112}{-42}
=-2+2/3
$